The equation W=Fd must be applied to this equation. However since we are not given enough information another equation
must be substituted in in order to find the equation. Where F=ma is substituted for F. Than A=V2-V1/T

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*Note*

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Work=Force multiplied by distance

Force=Mass multiplied by acceleration

Acceleration=Velocity final minus Velocity initial divided by time.

W=Fd

W=(ma)d

W=(m(V2-V1/t))d

Now that we haveo ur equation we must assume the following since this is only a scenerio:

Mass of the truck will be 3500kg.

Distance will be 100meters

V1=0M/s

V2=5m/s

t=15 seconds

W=(m(V2-V1/t))d

W=(3500)((5-0/15))100

W=(3500)(1/3)100

W=(1166.6)(100)

W=11666joules of energy

This means that the truck must produce 11666 joules of energy to accelerate

2

at .333 m/s in 15 seconds.

Now that we have found our work we may find out how much power is needed to accomplish this task.

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P=Power

W=Work

t=Time

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P=W/t

P=11666/15

P=777.73watts of power is used.