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Math Project
Automotive Engineering
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Conclusion

truck.jpg

Automotive Engineers must apply physics to prototype trucks in order to find out if they have enough power to sustain a useable towing capacity.
 
The equation W=Fd must be applied to this equation. However since we are not given enough information another equation must be substituted in in order to find the equation. Where F=ma is substituted for  F. Than A=V2-V1/T
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*Note*
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Work=Force multiplied by distance
Force=Mass multiplied by acceleration
Acceleration=Velocity final minus Velocity initial divided by time.
 
W=Fd
W=(ma)d
W=(m(V2-V1/t))d
 
Now that we haveo ur equation we must assume the following since this is only a scenerio:
Mass of the truck will be 3500kg.
Distance will be 100meters
V1=0M/s
V2=5m/s
t=15 seconds
 
W=(m(V2-V1/t))d
W=(3500)((5-0/15))100
W=(3500)(1/3)100
W=(1166.6)(100)
W=11666joules of energy
 
This means that the truck must produce 11666 joules of energy to accelerate
                2
at .333 m/s in 15 seconds.
 
Now that we have found our work we may find out how much power is needed to accomplish this task.
 
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P=Power
W=Work
t=Time
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P=W/t
P=11666/15
P=777.73watts of power is used.

Math Assignment 2005 Due March 18th